The Transmissibility of a vibrating system, for the values of (ω/ωn) >√2, will be 

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  1. Zero
  2. Less than one
  3. Equal to one
  4. Greater than one

Answer (Detailed Solution Below)

Option 2 : Less than one
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Concept:

In the vibration isolation system, the ratio of the force transmitted to the force applied is known as the isolation factor or transmissibility ratio.

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\(T.R = \frac{{{F_t}}}{{{F_0}}} = \frac{{\sqrt {1 + {{\left( {2\xi \frac{\omega }{{{\omega _n}}}} \right)}^2}} }}{{\sqrt {{{\left[ {1 - {{\left( {\frac{\omega }{{{\omega ^n}}}} \right)}^2}} \right]}^2} + {{\left( {2\xi \frac{\omega }{{{\omega _n}}}} \right)}^2}} }} \)

  • When ω/ωn = 0 ⇒ TR = 1, (independent of ζ)
  • When ω/ωn = 1 and ξ = 0 ⇒ TR = ∞, (independent of ζ)
  • When frequency ratio ω/ωn = √2, then all the curves pass through the point TR = 1 for all values of damping factor ξ.
  • When frequency ratio ω/ωn < √2, then TR > 1 for all values of damping factor ξ. This means that the force transmitted to the foundation through elastic support is greater than the force applied.
  • When frequency ratio ω/ωn > √2, then TR < 1 for all values of damping factor ξ. This shows that the force transmitted through elastic support is less than the applied force. Thus vibration isolation is possible only in the range of ω/ωn > √2. 
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