The time taken to face a workpiece of 80 mm diameter for the spindle speed of 90 rpm and cross feed of 0.3 mm/rev will be

This question was previously asked in
ESE Mechanical 2020 Official Paper
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  1. 4.12 min
  2. 3.24 min
  3. 2.36 min
  4. 1.48 min

Answer (Detailed Solution Below)

Option 4 : 1.48 min
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Detailed Solution

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Concept:

Time taken to face a work piece is given by

\({T_m} = \frac{L}{{fN}}\)

Here L = D/2, f – cross feed, N – spindle speed

Calculation:

Given:

D = 80 mm, f = 0.3 mm/rev, N = 90 rpm

fN = 27 mm/min, L = 40 mm

Time taken = 40/27 = 1.48 min
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