Question
Download Solution PDFThe smallest natural number which is divisible by 26, 20, 40 and 13 is:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
The numbers are: 26, 20, 40, 13
Formula used:
To find the smallest number divisible by these numbers, we need to calculate the LCM (Least Common Multiple).
Calculation:
Prime factorizations:
26 = 2 × 13
20 = 2² × 5
40 = 2³ × 5
13 = 13
LCM = Highest power of each prime factor:
LCM = 2³ × 5 × 13 = 8 × 5 × 13 = 520
∴ The smallest natural number divisible by 26, 20, 40, and 13 is 520.
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