The roots of the quadratic equation y2 + 4y + 4 = 0 are:

Given:

The quadratic equation y2 + 4y + 4 = 0

Concept:

For any given quadratic equation,

ax² + bx + c = 0

The roots \(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)

Solution:

The quadratic equation y2 + 4y + 4 = 0

\(y = {-b \pm \sqrt{b^2-4ac} \over 2a}\)

a = 1, b = 4, c = 4

\(y = {-4 \pm \sqrt{{(-4)}^2-4(1)(4)} \over 2(1)}\)

\(y = {-4 \over 2}=-2\)

y = -2, -2

Hence, option 1 is correct.