Testbook Logo
Exams SuperCoaching Test Series Skill Academy
More
English
Hindi

Question

Download Solution PDF

The molecular orbital involved in the interaction of the oxime shown below, with a base is

F1 Madhuri Teaching 06.02.2023 D21

This question was previously asked in
CSIR-UGC (NET) Chemical Science: Held on (16 Feb 2022)
Download PDF Attempt Online
View all CSIR NET Papers >
  1. σ* of O‐H
  2. σ* of C‐H
  3. σ of O‐H
  4. σ of C‐H

Answer (Detailed Solution Below)

Option 1 : σ* of O‐H
Free Tests
View all Free tests >
Free
Seating Arrangement
3.4 K Users
10 Questions 20 Marks 15 Mins
Start Now

Detailed Solution

Download Solution PDF

Explanation: 

The base will extract the  Hydrogen from the oxygen because of the electronegativity difference between oxygen and hydrogen.

The reaction will occur as follows: 

F1 Madhuri Teaching 06.02.2023 D22

Let's see the diagrammatic presentation of oxygen molecular orbitals:

F1 Teaching Priya 21-2-24 D1

As this can be easily seen from the molecular orbital diagram, the electron of hydrogen will be in the 2sσ* orbital of O-H.

Hence, the correct option is 1.

Download Solution PDF
Latest CSIR NET Updates

Last updated on Jun 5, 2025

-> The NTA has released the CSIR NET 2025 Notification for the June session.

-> The CSIR NET Application Form 2025 can be submitted online by 23rd June 2025

-> The CSIR UGC NET is conducted in five subjects -Chemical Sciences, Earth Sciences, Life Sciences, Mathematical Sciences, and Physical Sciences. 

-> Postgraduates in the relevant streams can apply for this exam.

-> Candidates must download and practice questions from the CSIR NET Previous year papers. Attempting the CSIR NET mock tests are also very helpful in preparation.

More Molecular Orbital Theory Questions

Q1.Consider the following statements regarding molecular orbitals of a water molecule. A. The photoelectron spectrum of water shows that two MOs containing the lone-pairs are not of the same energy. B. The O-H bond orbitals have a1 symmetry. C. The HOMO is predominantly an oxygen p orbital. D. Increasing H-O-H bond angle leads to the destabilization of the HOMO. The option containing the correct statements is
Q2.The ion having the highest bond order is
Q3.Choose the correct order of energy of 2σg and 1πu molecular orbitals for B2, C2 and O2:
Q4.The molecular orbital involved in the interaction of the oxime shown below, with a base is

More Chemical Bonding Questions

Q1.Consider the following reactions and the related statements. \(\rm AsF_5 + 2HF \rightleftharpoons P(cation) + Q (anion)\) \(\rm CIF_3 + 2HF \rightleftharpoons R(cation) + S (anion)\) A. P is bent B. Q is octahedral C. R is bent D. S is linear The option containing the correct statement is
Q2.Consider the following statements regarding molecular orbitals of a water molecule. A. The photoelectron spectrum of water shows that two MOs containing the lone-pairs are not of the same energy. B. The O-H bond orbitals have a1 symmetry. C. The HOMO is predominantly an oxygen p orbital. D. Increasing H-O-H bond angle leads to the destabilization of the HOMO. The option containing the correct statements is
Q3.CO2 is isostructural with -
Q4.Which one of the following will have tetrahedral disposition?
Q5.Based on VSEPR theory, the predicted shape of [XeF5]- is ·
Q6.An sp3 hybrid orbital contains -
Q7.Two pi and half sigma bonds are present in -
Q8.The isoelectronic set of ions is -
Q9.CO2 is isostructural with which of the following?
Q10.The statement(s) that correctly describe(s) the molecular orbital (MO) diagram of HO- (hydroxyl radical) is/are (consider the O-H bond to be along the x-axis) A. The Highest Occupied Molecular Orbital (HOMO) is a non-bonded MO that is predominantly formed with 2pz and 2py atomic orbitals (AOs) of O-atom. B. The HOMO is a σ-bonded MO that is predominantly formed by the overlap of H (1s) and O (2s) AOs. C. The σ-bonding MO is formed by the overlap of H(1s) and O(2pz) AOs. D. The σ-bonding MO is formed by the overlap of H(1s) and O(2px) AOs.

More Chemical Sciences Questions

Q1.Match the List I and List II: List - I List - II (A) α -emission (p) Z increase (B) β -emission (q) n/p increase (C) β+ -emission (r) n/p decrease (S) K-electron capture (s) X- ray emission     (t) Z decrease  
Q2.The major product formed in the following reaction sequence is
Q3.Reaction of white phosphorus with sulfur gives a mixture of products A, B and C. The 31P NMR spectral features of the resultant mixture are shown below. The products A, B and C, respectively, are
Q4.The correct order of the rate for the following rearrangement that involves a three membered intermediate is P: X = -CH=CH2 Q: X = Me3CC(O)- R: X = -C≡N
Q5.For elements P, Q, R and S, the corresponding valencies and average orbital energies are listed below. Element  Valency  Average Valence Orbital Energy (eV) P i  -19 Q j  -22.5 R k -9 S l -7 Based on the Van-Arkel diagram, the correct option from the following A. SjQl is covalent. B. PkRi is ionic. C. RISk is metallic. D. PjQi is covalent is
Q6.The unperturbed energies (in eV) of a three-level system are ε0 = 2, ε1 = 4 and ε2 = 6. The matrix elements of a perturbation V (in eV) between the levels (in subscript) are V10 = 4, V20 = 6 and V12 = 10. The second-order correction to the ground state energy (in eV) in the presence of perturbation V is
Q7.Two moles of calcium phosphate on reduction with carbon in the presence of silica resulted in the formation of a phosphorus compound X in 90% yield. The weight of X is (Atomic weight, Ca 40, P 31, Si 28, O 16, C 12, H 1)
Q8.The β-activity of 0.9 g of carbon from the wood of a present-day tree is 0.25 Bq. If the activity of 0.9 g carbon isolated from the wood of an ancient artifact is 0.19 Bq under the same conditions (14C : t1/2 = 5730 years), the age of the ancient artifact is
Q9.At a given temperature, an atom accesses 2S1/2, 2P1/2 and 2P3/2 atomic states with energies 0 kBT, 0.5 kBT and 0.5 kBT, respectively. The fraction of atoms in the P states is
Q10.From the following 18-electron complex(es), identify those which predominantly undergoes/undergo substitution reaction by P(OMe)3 via an associative mechanism. A. Mn(CO)4NO B. trans-Cr(CO)4(PPh3)2 C. cis-Mn(CO)5Br D. (η5-C5H5)Co(CO)2 The correct option is
Super Coaching
CSIR NET Test Series
CSIR NET Previous Year Papers
CSIR NET Syllabus
CSIR NET Study Material
CSIR NET Preparation Tips
CSIR NET Books
CSIR NET Important Topics
Testbook Edu Solutions Pvt. Ltd.
1st & 2nd Floor, Zion Building,
Plot No. 273, Sector 10, Kharghar,
Navi Mumbai - 410210
[email protected]
Toll Free:1800 833 0800
Office Hours: 10 AM to 7 PM (all 7 days)
Company
About usCareers We are hiringTeach Online on TestbookPartnersMediaSitemap
Products
Test SeriesTestbook PassOnline CoursesOnline VideosPracticeBlogRefer & EarnBooks
Our Apps
Follow us on
Copyright © 2014-2022 Testbook Edu Solutions Pvt. Ltd.: All rights reserved
User PolicyTermsPrivacy
Get Free Access Now
Hot Links： teen patti all game teen patti club teen patti mastar teen patti casino apk teen patti bonus