Question
Download Solution PDFThe maximum efficiency of transmission of power through a pipe is
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFExplanation:
Efficiency of power transmission through pipe is given by,
\(\eta =\frac{H-{{h}_{f}}}{H}\)
Here, H = head available at inlet
hf = frictional head loss
For maximum power transmission through pipe,
\({{h}_{f}}=\frac{H}{3}\)
\(\Rightarrow \eta =\frac{H-\frac{H}{3}}{H}=\frac{2}{3}=0.6667\)
So, ηmax = 66.67%
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