Question
Download Solution PDFThe magnitude of the magnetic field at a distance 'R' from a long, straight wire carrying a current 'I' is equal to ____________. ( 'µ0' is permeability of free space)
This question was previously asked in
SSC Scientific Assistant Physics Official Paper (Held On: 25 November 2017 Shift 2)
- μoI / (πR2)
- 2μoI / R
- μoI / (2πR)
- μoI / R2
Answer (Detailed Solution Below)
Option 3 : μoI / (2πR)
Crack SSC IMD with
India's Super Teachers
FREE
Demo Classes Available*
Explore Supercoaching For FREE
Free Tests
View all Free tests >
Free
SSC Scientific Assistant Physics Official Paper (Held On: 22 November 2017 Shift 1)
17.2 K Users
200 Questions
200 Marks
120 Mins
Detailed Solution
Download Solution PDFCONCEPT:
The magnetic field at point P due to a straight conductor is given by:
B = \(μ_0 I \over{2\pi d}\)
where B is the magnetic field at point P, μ0 permeability of the medium I is the current in the wire and d is the distance from the wire to that point.
EXPLANATION:
Here d = R
At distance R from an infinitely long straight current-carrying conductor, the magnetic field is:
B = \(μ_0 I \over{2\pi R}\)
The correct answer is option 3.
India’s #1 Learning Platform
Start Complete Exam Preparation
Daily Live MasterClasses
Practice Question Bank
Mock Tests & Quizzes
Trusted by 7.2 Crore+ Students
More Magnetic Field due to a Current Element Questions
More Moving Charges and Magnetism Questions
Crack SSC IMD with
India's Super Teachers
Atul Varshney
Testbook
Shailendra Kantak
Testbook
Explore Supercoaching For FREE
Suggested Test Series
View All >
309 Total Tests with
6 Free Tests
Start Free Test
Suggested Exams