The greatest number that divides 38, 45 and 52 leaves remainders 2, 3 and 4 respectively is:

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  1. 4
  2. 5
  3. 6
  4. None of the above 

Answer (Detailed Solution Below)

Option 3 : 6
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Given:

Numbers: 38, 45, 52

Remainders: 2, 3, 4

Formula used:

To find the greatest number that divides these numbers leaving specific remainders:

Required number = HCF of (38 - 2), (45 - 3), (52 - 4)

Calculation:

38 - 2 = 36

45 - 3 = 42

52 - 4 = 48

Finding HCF of 36, 42, and 48:

Prime factors of 36: 2 × 2 × 3 × 3

Prime factors of 42: 2 × 3 × 7

Prime factors of 48: 2 × 2 × 2 × 2 × 3

Common factors: 2 × 3 = 6

⇒ HCF = 6

The greatest number that divides 38, 45, and 52, leaving remainders 2, 3, and 4, respectively, is 6.

∴ The correct answer is option (3).

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