Question
Download Solution PDFThe Fourier series for f(x) = sin2 x defined over the range -π ≤ x ≤ π is
This question was previously asked in
UPSC IES Electrical 2022 Prelims Official Paper
Answer (Detailed Solution Below)
Option 1 : \(\frac{1}{2}-\frac{\cos 2x}{2}\)
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ST 1: UPSC ESE (IES) Civil - Building Materials
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Detailed Solution
Download Solution PDFCalculation:
From the trigonometric identity:
cos (2x) = 1 - 2sin2(x)
2sin2(x) = 1 - cos (2x)
f(x) = sin2 x = \(\frac{1}{2}-\frac{\cos 2x}{2}\)
Hence, option 1 is correct.
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