The eigenvectors of the matrix \(\left[ {\begin{array}{*{20}{c}} 1&2\\ 0&2 \end{array}} \right]\) are written in the form \(\left[ {\begin{array}{*{20}{c}} 1\\ a \end{array}} \right]and\left[ {\begin{array}{*{20}{c}} 1\\ b \end{array}} \right]\). What is (a + b) ?

  1. 0
  2. 1/2
  3. 1
  4. 2

Answer (Detailed Solution Below)

Option 2 : 1/2

Detailed Solution

Download Solution PDF

Concept:

Characteristics polynomial of a matrix:

Let A be a square matrix of order n and λ be any scalar quantity. Then the polynomial in λ of degree n formed by solving the characteristic equation |A - λI| = 0 is called the characteristics polynomial of the matrix.

Eigenvalues:

The roots of the characteristic equation are called the eigenvalues or characteristic roots of latent roots of matrix A.

Eigenvectors:

If λ is the eigenvalue of matrix A then a non-zero vector X that satisfies AX = λX is called the eigenvector of the matrix corresponding to the eigenvalue λ.

Calculation:

\(\left[ {\begin{array}{*{20}{c}} {\left( {1 - \lambda } \right)}&2\\ 0&{\left( {2 - \lambda } \right)} \end{array}} \right] =0\)

\(\Rightarrow \left( {1 - \lambda } \right)\left( {2 - \lambda } \right) = 0\)

∴ λ = 1, 2

Putting the value of λ = 1

⇒ \(\left[ {\begin{array}{*{20}{c}} 0&2\\ 0&1 \end{array}} \right]\left[ {\begin{array}{*{20}{c}} 1\\ a \end{array}} \right] = 0\)

⇒ a = 0

Putting λ = 2,

\(\left[ {\begin{array}{*{20}{c}} { - 1}&2\\ 0&0 \end{array}} \right]\left[ {\begin{array}{*{20}{c}} 1\\ b \end{array}} \right] = 0\)

⇒ \({\rm{b\;}} = \frac{1}{2}{\rm{\;}}\)

∴ \({\rm{a\;}} + {\rm{\;b\;}} = \frac{1}{2}{\rm{\;}}\)

Latest BPSC Assistant Professor Updates

Last updated on May 9, 2025

-> The BPSC Assistant Professor last date to apply online has been extended to 15th May 2025 (Advt. No. 04/2025 to 28/2025).

-> The BPSC Assistant Professor Notification 2025 has been released for 1711 vacancies under Speciality (Advt. No.04/2025 to 28/2025).

-> The recruitment is ongoing for 220 vacancies (Advt. No. 01/2024 to 17/2024).

-> The salary under BPSC Assistant Professor Recruitment is approximately Rs 15600-39100 as per Pay Matrix Level 11. 

-> The selection is based on the evaluation of academic qualifications &  work experience and interview.

-> Prepare for the exam using the BPSC Assistant Professor Previous Year Papers. For mock tests attempt the BPSC Assistant Professor Test Series.

More Eigenvectors Questions

More Linear Algebra Questions

Get Free Access Now
Hot Links: teen patti sequence dhani teen patti teen patti lotus teen patti 51 bonus teen patti gold old version