The distance between two parallel shafts connected by Oldhams coupling is 20 mm. The driving shaft revolves at 200 R.P.M. Determine the maximum velocity of sliding.

Question

Question

This question was previously asked in

NPCIL SA/ST ME GJ held on 07/11/2019 Shift-1

Answer 1

Concept:

Maximum sliding velocity in Oldham’s coupling

= Peripheral velocity along the circular path

= angular velocity of shaft × distance between shafts = ω × d

Calculation:

Given:

d = 20 mm = 0.020 m, N = 200 rpm

\(\therefore {\rm{\omega }} = \frac{{2\pi \times 200}}{{60}} = 20.94~\frac{{rad}}{s}\)

Maximum velocity of sliding = ω × d = 20.94 × 0.020

= 0.418 m/s