Question
Download Solution PDFThe displacement of a car during its journey is given by s = xt2 - yt + z where x, y and z are constants and t is the time. The acceleration of the car at t = 4 s is
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFThe correct answer is option 2) i.e. 2x units
CONCEPT:
- Velocity: The rate of change in displacement is called velocity.
- Acceleration: The rate of change in velocity is called acceleration.
Let the displacement of a particle be x.
| Velocity, v | \(\frac{dx}{dt}\) |
| Acceleration, a | \(\frac{dv}{dt}\) |
CALCULATION:
Given that: Displacement , s = xt2 - yt + z
- The velocity of the car,
\(\Rightarrow v = \frac{ds}{dt} = \frac{d(xt^2 -yt + z)}{dt}= 2xt - y\)
- Acceleration of the car,
\(\Rightarrow a = \frac{dv}{dt} = \frac{d(2xt - y)}{dt} = 2x\)
- The acceleration of the car is time-independent and therefore, at any instant, the acceleration will be 2x.
Last updated on May 21, 2025
-> Indian Airforce Agniveer Group X 2025 Last date has been extended.
-> Candidates can apply online from 7th to 2nd February 2025.
-> The online examination will be conducted from 22nd March 2025 onwards.
-> The selection of the candidates will depend on three stages which are Phase 1 (Online Written Test), Phase 2 ( DV, Physical Fitness Test, Adaptability Test), and Phase 3 (Medical Examination).
-> The candidates who will qualify all the stages of selection process will be selected for the Air Force Group X posts & will receive a salary ranging of Rs. 30,000.
-> This is one of the most sought jobs. Candidates can also check the Airforce Group X Eligibility here.