The condition for maximum efficiency in transformer is

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  1. Copper loss = 0
  2. Core loss = 0
  3. Copper loss = Core loss
  4. Copper loss = 2 × Core loss

Answer (Detailed Solution Below)

Option 3 : Copper loss = Core loss
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The transformer will give the maximum efficiency when their copper loss is equal to the iron loss.

Copper loss:

A loss in a transformer that takes place in the winding resistance of a transformer is known as the copper loss.

Copper loss = i2R

Iron loss:

Iron losses = Eddy current loss + hysteresis loss

Eddy current loss = KtfB2

Hysteresis loss = Kf Bη

Where, Ke & Kh are constant

f = Supply frequency

B = Flux density

t = thickness

Efficiency is maximum at some fraction x of full load:

\(x = \sqrt {\frac{{{W_i}}}{{{W_{cu}}}}}\)

Where Wi = iron losses

Wcu = copper losses

Load at maximum efficiency \(= Full\;load \times \sqrt {\frac{{{W_i}}}{{{W_{cu}}}}} = Full\;load \times \sqrt {\frac{B}{A}} \)

kVA at maximum efficiency is given by,

\(kVA\;at\;{η _{max}} = full\;load\;kVA \times \sqrt {\frac{{{W_i}}}{{{W_{cu}}}}}\)

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