Question
Download Solution PDFTable shows the marks of 130 students of class 10th.
Median of given data is:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFFormula used:
Where the median class is the class interval whose cumulative frequency ≥ N/2.
N = sum of frequencies, L = lower limit of the median class,
f = frequency of median class, h = width of the class
C = cumulative frequency of the class just preceding the median class.
Calculation:
| Class | Frequency (f) |
Cumulative frequency (C) |
| 20 - 30 | 0 | 0 |
| 30 - 40 | 4 | 4 |
| 40 - 50 | 18 | 22 |
| 50 - 60 | 60 | 82 |
| 60 - 70 | 33 | 115 |
| 70 - 80 | 15 | 130 |
We can see that, the sum of frequency
N = 130
N/2 = 65
Hence, 50 - 60 will be the median class, where
L = 50, f = 60, h = 10 and c = 22
\(Median = L + \frac{\frac{N}{2}\ -\ C}{f}\times h\)
\(⇒ Median = 50 + \frac{\frac{130}{2}\ -\ 22}{60}\times 10\)
⇒ Median = 57.16
∴ The median of the data is 57.16
Last updated on May 30, 2025
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