Solve the equation \(3^{2x^2}-2 (3^{x^2+x+6})+3^{3(x+6)}=0\)

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Maha TAIT Official Paper (Held On 13 Dec 2017 Shift 1)
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  1. {x = -3, -2}
  2. {x = 3, 2}
  3. {x = -3, 2}
  4. {x = 3, -2}

Answer (Detailed Solution Below)

Option 4 : {x = 3, -2}
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Detailed Solution

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Given:

\(3^{2x^2}-2 (3^{x^2+x+6})+3^{3(x+6)}=0\)

Calculation:

(3x2)− 2.3x2⋅3(x+6) + (3(x+6))2 = 0

⇒ (\({3^x}^2\)−3x+6)= 0

\({3^x}^2\) = 3x+6

⇒ x= x+6

⇒ x2 − x − 6 = 0

⇒ x− 3x + 2x − 6 = 0

⇒ (x − 3)(x + 2) = 0

x = 3 or x = −2 

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