इलेक्ट्रिक हीटरच्या दोन टोकाच्या टर्मिनल्समधील संभाव्य फरक 220 V आहे आणि त्याद्वारे प्रवाह 0.5 A आहे. हीटरच्या टर्मिनल्समधील संभाव्य फरक 120 V वर कमी केल्यास हीटरद्वारे प्रवाह किती असेल?

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UPSC NDA-II (General Ability) Official Paper-I (Held On: 03 Sept, 2023)
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  1. 1.0 A
  2. 0.5 A
  3. 0.27 A
  4. 0.7 A

Answer (Detailed Solution Below)

Option 3 : 0.27 A
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योग्य उत्तर 0.27 A आहे.

दिलेले आहे,

संभाव्य फरक (V) = 220 V.

विद्युतप्रवाह (I) = 0.5 A.

ओहमचा नियम वापरल्यास:

\(V = {I \times R}\)

प्रतिरोध (R) = \(R = {V \over I} = {220 \over 0.5}\)

R= 440 Ω

संभाव्य फरक 120 V पर्यंत कमी केल्यास

V = 120 V

R= 440 Ω

विद्युतप्रवाह (I) = \({120 \over 440}\) = 0.27 A

संभाव्य फरक 120 V पर्यंत कमी केल्यास हीटर 0.27 A विद्युतप्रवाह काढेल.

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