Indian standard specifies ______ as the specific temperature for reporting the specific gravity

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JKSSB JE Civil Jal Shakti 6 Dec 2022 Official Paper (Shift 2)
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  1. 28°C
  2. 25°C
  3. 26°C
  4. 27°C

Answer (Detailed Solution Below)

Option 4 : 27°C
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Detailed Solution

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Explanation:

Specific Gravity:

  • Specific Gravity is a dimensionless quantity that is defined as the ratio of the density of a substance to the density of the water at a temperature of 27°C.
  • It is common to use the density of water at 4°C as a reference point as water at this point has the highest density of 1000 kg/m3.
  • The specific gravity shall be calculated at 27°C.

If the room temperature is different than 27°C, the following corrections shall be done:

G’ = KG

Where G’ = corrected specific gravity at 27°C, and

\(K = \frac{{{\rm{Relative\;density\;of\;water\;at\;room\;temperature}}}}{{{\rm{Relative\;density\;of\;water\;at\;}}27^\circ {\rm{\;C}}}}\)

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