If the velocity gradient of a fluid is 24000 sec-1, force required to move a fluid between plate is 3 N/m2, what will be the fluid viscosity between the plates?

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  1. \( 1.25 \times 10^{-4} \frac{\mathrm{Ns}}{\mathrm{m}^2} \\\)
  2. \( 1.93 \times 10^{-4} \frac{\mathrm{Ns}}{\mathrm{m}^2} \\\)
  3. \( 1.97 \times 10^{-5} \frac{\mathrm{Ns}}{\mathrm{m}^2} \\\)
  4. \( 2.67 \times 10^{-3} \frac{\mathrm{Ns}}{\mathrm{m}^2} \)

Answer (Detailed Solution Below)

Option 1 : \( 1.25 \times 10^{-4} \frac{\mathrm{Ns}}{\mathrm{m}^2} \\\)
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Detailed Solution

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Concept:

The viscosity of a fluid can be calculated using Newton's law of viscosity:

\(\tau = \mu \frac{du}{dy}\)

Calculation:

Given:

  • Velocity gradient, dudy=24000sec1
  • Shear stress, τ=3N/m2

The viscosity is given by:

\(\mu = \frac{\tau}{\frac{du}{dy}}\)

Substitute the given values:

\(\mu = \frac{3}{24000} = 1.25 \times 10^{-4} \, \text{N} \cdot \text{s/m}^2\)

The fluid viscosity between the plates is 1.25×1.25×104Ns/m2

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