Question
Download Solution PDFIn free space, \({\bf{E}}\left( {{\rm{z}},{\rm{t}}} \right) = {10^3}{\rm{sin}}\left( {{\rm{\omega t}}-{\rm{\beta z}}} \right)\hat y\). Obtain H(z,t).
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Any vector quantity can be represented as the product of magnitude and vector quantity, i.e.
\(\vec A = \left| A \right|.\;\hat u\)
|A| = Magnitude of the vector quantity.
û = Unit direction vector.
Poynting vector:
It states that the cross product of electric field vector (E) and magnetic field vector (H) at any point is a measure of the rate of flow of electromagnetic energy per unit area at that point that is
\( \vec P = \vec E \times \vec H\)
Where P = Poynting vector, E = Electric field and H = Magnetic field
The Poynting vector describes the magnitude and direction of the flow of energy in electromagnetic waves.
The unit of the Poynting vector is watt/m2
The ratio \(\frac{{\left| E \right|}}{{\left| H \right|}}\) for the wave is equal to the intrinsic impedance of the medium, η.
\(\frac{E}{H} = {\eta _0} = 377\;{\rm{\Omega }} = 120\;\pi \)
Analysis:
The direction of propagation = +z direction
Electric field vector = +y direction
The direction of the magnetic field will be such that the Poynting vector theorem is satisfied
i.e. P = E × H
∴ The magnetic field must be along (-ax) direction.
The magnitude will be:
\(\frac{{\left| E \right|}}{{\left| H \right|}} = 377\)
\(H = \frac{{\left| E \right|}}{{377}} = \frac{{{{10}^3}}}{{377}} = 2.65\)
∴ The magnetic field vector will be:
\(\vec H\) (z, t) = |H| sin (ωt – βz) (-ax)
= -2.65 sin (ωt - βz) ax
Last updated on Jun 19, 2025
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