Question
Download Solution PDFIn a cricket match, a batsman hits a six 8 times out of 60 balls he plays. What is the probability that on a ball played he does not hit a six?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFFormula used:
Probability of occurrence of the event:
P(E) = \(\frac{n(E)}{n(S)}\)
Where,
n(E) = Number of favorable outcome
n(S) = Number of possible outcome
Calculation:
A batsman hits sixes 8 times out of 60 balls then
Probability of getting sixes
P(A) = \(\rm \frac{8}{60}\) = \(\rm \frac{2}{15}\)
The probability that he does not hit a six
P(A̅) = 1 − \(\rm \frac{2}{15}\)
⇒ P(A̅) = \(\rm \frac{13}{15}\)
∴ Required probability is \(\rm \frac{13}{15}\).
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