Question
Download Solution PDFIf the average sewage from the city is 95 × 106 litres/day and the average 5 days BOD is 300mg / litre, then the population equivalent will be (where, domestic sewage quantity is 0.08 kg.person/day)
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFExplanation
Population equivalent
The total nos. of individuals releasing the BOD at the rate of average standard BOD of the domestic sewage to that released by the industry is called population equivalent.
Population equivalent = \(\frac{Industrial BOD}{Average Standard BOD}\)
Calculation:
Average savage from city = 95 × 106 l\day
Average 5 day of BOD = 300 mg/l
Domestic sewage quantity i.e Avg = 0.08 Kg person/day
Now Industrial BOD = 95 × 106 l/day × 300 mg/l
\(= 95\times10^6\times\frac{l}{day}\)\(\times300\times10^{-6}\times\frac{kg}{l}\)
= 28500 \(\frac{kg}{day}\)
Now population equivalent
\(=\frac{2850\ kg/day}{0.08\ kg\ person\ /day}\)
= 356250
Last updated on Jun 12, 2025
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