Question
Download Solution PDFIf the actual length of a Euler's column with both ends fixed is L, then, the effective length of that column will be:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Euler’s critical buckling load \(\left( {{P}_{e}} \right)=\frac{{{\pi }^{2}}\cdot E\cdot {{I}_{min}}}{L_{e}^{2}}\)
Where, Imin = minimum area moment of Inertia, E = young’s modulus of elasticity, Le = Equivalent length = L ⋅ α
α for different loading conditions are different
Effective length of column (Le) \(=\dfrac{\ell}{2}\) = 0.5 L
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