Question
Download Solution PDFएक संतुलित स्टार संयोजित लोड की फेज प्रतिबाधा ZY = 40 + j30 Ω है। इसके समतुल्य Δ-संयोजित लोड की फेज प्रतिबाधा कितनी होगी?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFस्टार से डेल्टा रूपांतरण
स्टार से जुड़े प्रतिरोधक का डेल्टा समतुल्य है:
\(R_A={R_1R_2+R_2R_3+R_1R_3\over R_3}\)
\(R_B={R_1R_2+R_2R_3+R_1R_3\over R_2}\)
\(R_C={R_1R_2+R_2R_3+R_1R_3\over R_1}\)
यदि स्टार में जुड़े सभी प्रतिरोध 'R' के बराबर हैं, तो डेल्टा समतुल्य प्रतिरोध है:
\(R_A=R_B=R_C={3R}\)
गणना
दिया गया है, ZY = 40 + j30 Ω
ZΔ = 3 x (40 + j30)
ZΔ = 120 + j90 Ω
Last updated on May 29, 2025
-> MPPGCL Junior Engineer result PDF has been released at the offiical website.
-> The MPPGCL Junior Engineer Exam Date has been announced.
-> The MPPGCL Junior Engineer Notification was released for 284 vacancies.
-> Candidates can apply online from 23rd December 2024 to 24th January 2025.
-> The selection process includes a Computer Based Test and Document Verification.
-> Candidates can check the MPPGCL JE Previous Year Papers which helps to understand the difficulty level of the exam.