स्थानांतरण फलन \(\frac{1+\frac{s}{4}}{1+\frac{s}{25}}\) वाला नेटवर्क _________ की आवृत्ति पर अधिकतम फेज अग्रता प्रदान करेगा।

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ESE Electronics 2013 Paper 2: Official Paper
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  1. 4 rad / sec
  2. 25 rad / sec
  3. 10 rad / sec
  4. 100 rad / sec

Answer (Detailed Solution Below)

Option 3 : 10 rad / sec
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Detailed Solution

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अवधारणा:

मानक फेज अग्रता प्रतिकारी नेटवर्क इस प्रकार दिया गया है:

\(\frac{{{V_0}\left( s \right)}}{{{V_i}\left( s \right)}} = \frac{{\alpha \left( {1 + sT} \right)\;}}{{\left( {1 + \alpha sT} \right)}}\) ------(1)

अधिकतम फेज निम्न पर होता है

\(ω_m=\frac{1}{T√{\alpha }}\)

अधिकतम फेज (ϕm)

\(sin{\phi _m} = \frac{{1 - \alpha }}{{1 + \alpha }}\)

गणना:

दिया हुआ:

\(G(s)=\frac{1+\frac{s}{4}}{1+\frac{s}{25}}\)

इसकी तुलना मानक स्थानांतरण फलन यानी समीकरण 1 से करें

\(T=\frac{1}{4}, \ \alpha T=\frac{1}{25}\)

अधिकतम फेज निम्न पर होता है

\(ω_m=\frac{1}{T√{\alpha }}=√{\frac{1}{\alpha T}\frac{1}{T}}\)

ωm = √(100) = 10 rad/sec

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