Question
Download Solution PDF100 प्रेक्षणों का समांतर माध्य 50 है। यदि प्रत्येक प्रेक्षण में से 5 घटा दिया जाए और फिर 20 से विभाजित कर दिया जाए, तो नया समांतर माध्य क्या होगा?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFगणना:
दिया गया है,
प्रेक्षणों की संख्या, n = 100
मूल समांतर माध्य, \( \bar{x} = 50 \)
प्रत्येक प्रेक्षण पर लागू परिवर्तन:
नया मान, \( x' = \frac{x - 5}{20} \)
नया समांतर माध्य है,
\( \bar{x}' = \frac{\bar{x} - 5}{20} \)
\( \bar{x}' = \frac{50 - 5}{20} = \frac{45}{20} = 2.25 \)
∴ नया समांतर माध्य 2.25 है।
इसलिए, सही उत्तर विकल्प 1 है।
Last updated on Jul 8, 2025
->UPSC NDA Application Correction Window is open from 7th July to 9th July 2025.
->UPSC had extended the UPSC NDA 2 Registration Date till 20th June 2025.
-> A total of 406 vacancies have been announced for NDA 2 Exam 2025.
->The NDA exam date 2025 has been announced. The written examination will be held on 14th September 2025.
-> The selection process for the NDA exam includes a Written Exam and SSB Interview.
-> Candidates who get successful selection under UPSC NDA will get a salary range between Rs. 15,600 to Rs. 39,100.
-> Candidates must go through the NDA previous year question paper. Attempting the NDA mock test is also essential.