\(\mathop \smallint \nolimits_{ - 7}^2 \left( {{t^2} + {t^3} + 1} \right)\delta \left( {t - 3} \right)dt = \_\_\_\_\)  का मान क्या है?

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Option 4 : 0
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संकल्पना:

इकाई आवेग फलन:

इसे \(\delta \left( t \right) = \left\{ {\begin{array}{*{20}{c}} {\infty ,\;\;t = 0}\\ {0,\;\;t \ne 0} \end{array}} \right.\)  के रूप में परिभाषित किया गया है,

इकाई आवेग के पृथक-समय प्रारूप को निम्न द्वारा परिभाषित किया गया है

\(\delta \left[ n \right] = \left\{ {\begin{array}{*{20}{c}} {1,\;\;n = 0}\\ {0,\;\;n \ne 0} \end{array}} \right.\)

गुण:

1. \(\mathop \smallint \limits_{ - \infty }^\infty \delta \left( t \right)dt = 1\)

2. \(\delta \left( {at} \right) = \frac{1}{{\left| a \right|}}\delta \left( t \right)\)

3. x(t) δ(t – t0) = x(t0)

4. \(\mathop \smallint \limits_{ - \infty }^\infty x\left( t \right)\delta \left( {t - {t_o}} \right)dt = x\left( {{t_0}} \right)\)

5. \(\mathop \smallint \limits_{ - \infty }^\infty f\left( t \right)\delta \left( {at + b} \right)dt = \mathop \smallint \limits_{ - \infty }^\infty f\left( t \right)\frac{1}{{\left| a \right|}}\delta \left( {t + \frac{b}{a}} \right)dt\)

6. \(\mathop \smallint \limits_{ - \infty }^\infty x\left( t \right){\delta ^n}\left( {t - {t_o}} \right)dt = {\left. {\frac{{{d^n}x}}{{d{t^n}}}} \right|_{t = {t_0}}}\)

गणना:

\(Let \ y \ =\mathop \smallint \nolimits_{ - 7}^2 \left( {{t^2} + {t^3} + 1} \right)\delta \left( {t - 3} \right)dt\)

उपरोक्त समीकरण में गुण (3) का प्रयोग करने पर:

t = 3 पर, यह सीमा के बाहर है। 

इसलिए y = 0 या हम कह सकते हैं कि

\(\mathop \smallint \nolimits_{ - 7}^2 \left( {{t^2} + {t^3} + 1} \right)\delta \left( {t - 3} \right)dt =0\)

अतः विकल्प (4) सही उत्तर है। 

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