Question
Download Solution PDFदिखाए गए चित्र में, BC एक जीवा है और CD बिंदु C से होकर जाने वाली स्पर्शरेखा है। यदि ∠AOC = 112° है, तो ∠ACD का मान ज्ञात कीजिए।
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया है :
BC एक जीवा है और CD बिंदु C से होकर जाने वाली स्पर्शरेखा है।
∠AOC = 112°
प्रयुक्त अवधारणा :
केंद्र पर अंतरित कोण = 2 × वृत्त के चाप पर अंतरित कोण
गणना :
ΔOAC में,
∠OAC = ∠ACO
⇒ 112° + 2x = 180°
⇒ 2x = 180° - 112°
⇒ 2x = 68°
⇒ x = 34°
अब, ∠ACD = ∠OCD - ∠OCA
⇒ 90° - 34° = 56°
∴ सही उत्तर 56° है।
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