Question
Download Solution PDFशुद्ध लोहे के कार्य खंड के साथ एक ECM में, 5 cm³/min का MRR आवश्यक है। आवश्यक धारा क्या होगी? [लोहे का परमाणु भार = 56g, संयोजकता = 2, लोहे का घनत्व = 7.8g/cm³ और F = 96500 कूलम्ब]
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसंकल्पना:
विद्युत रासायनिक मशीनिंग (ECM) में आवश्यक धारा इस प्रकार दी गई है:
\( I = \frac{\text{MRR} \times \rho \times Z \times F}{M \times 60} \)
दिया गया है:
\( \text{MRR} = 5~\text{cm}^3/\text{min},~\rho = 7.8~\text{g/cm}^3,~Z = 2,~M = 56,~F = 96500~\text{C} \)
गणना:
\( I = \frac{5 \times 7.8 \times 2 \times 96500}{56 \times 60} = \frac{7524000}{3360} \approx 2240~\text{A} \)
Last updated on Jul 1, 2025
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