Question
Download Solution PDF23.1 सेमी लंबाई का एक चाप, केंद्र पर 18° का कोण अंतरित करता है। वृत्त का क्षेत्रफल कितना है? [
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया है:
चाप की लंबाई = 23.1 सेमी
चाप द्वारा केंद्र पर बनाया गया कोण = 18°
प्रयुक्त सूत्र:
चाप की लंबाई = (2 × π × R × θ)/360
वृत्त का क्षेत्रफल = π × R2
जहाँ, R = त्रिज्या
गणना:
चाप की लंबाई = (2 × π × R × θ)/360
⇒ 23.1 = (2 × 22 × R × 18)/(360 × 7)
⇒ 23.1 = (22 × R)/(10 × 7)
⇒ R = (2.1 × 70)/2 = 73.5 सेमी
वृत्त का क्षेत्रफल = π × R2
⇒ (22/7) × 73.5 × 73.5
⇒ 22 × 10.5 × 73.5
⇒ 16978.50 सेमी2
∴ सही उत्तर 16978.50 सेमी2 है।
Last updated on Jul 16, 2025
-> This year, the Staff Selection Commission (SSC) has announced approximately 14,582 vacancies for various Group B and C posts across government departments.
-> The SSC CGL Tier 1 exam is scheduled to take place from 13th to 30th August 2025.
-> Aspirants should visit ssc.gov.in 2025 regularly for updates and ensure timely submission of the CGL exam form.
-> Candidates can refer to the CGL syllabus for a better understanding of the exam structure and pattern.
-> The CGL Eligibility is a bachelor’s degree in any discipline.
-> Candidates selected through the SSC CGL exam will receive an attractive salary. Learn more about the SSC CGL Salary Structure.
-> Attempt SSC CGL Free English Mock Test and SSC CGL Current Affairs Mock Test.