एक आयत की लम्बाई 48 सेमी है और चौड़ाई 14 सेमी है। यदि विकर्ण बड़ी भुजा के साथ θ कोण बनाता है, तब (sec θ + cosec θ) का मान किसके बराबर होगा?

This question was previously asked in
CDS Maths Previous Paper 9 (Held On: 2 Feb 2020)
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दिया गया है:

एक आयत 48 सेमी लंबा और 14 सेमी चौड़ा है

प्रयुक्त सूत्र:

sec θ = कर्ण/आधार

cosec θ = कर्ण/लंब

पाइथागोरस प्रमेय

(कर्ण)2 = (लंब)2 +(आधार)2

गणना:

त्रिभुज ABC एक समकोण त्रिभुज है:

कर्ण = AC = x =  = 50

यहाँ,

Sec θ = AC/AB = 50/48

Cosec θ = AC/BC = 50/14

अतः,

(sec θ + cosec θ) = (50/48) + (50/14) = 1550/336 = 775/168 

∴ sec θ + cosec θ का मान 775/168 है

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