एक कार्नोट ऊष्मा पंप 27°C और 327°C के बीच काम करता है। इसका COP क्या होगा?

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ESE Mechanical 2014 Official Paper - 1
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  1. 0.09
  2. 1.00
  3. 1.09
  4. 2.0

Answer (Detailed Solution Below)

Option 4 : 2.0
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अवधारणा:

F2 Sumit Madhu 10.08.20 D 2

\({\rm{COP\;of\;Carnot\;Heat\;pump}} = \frac{{{T_1}}}{{{T_1} - {T_2}}}\)

गणना:

दिया हुआ:

T1 = 327° C = 600 K, T2 = 27° C = 300 K

\(\therefore COP = \frac{{{T_1}}}{{{T_1} - {T_2}}}\)

\(\therefore COP = \frac{{600}}{{600 - 300}} = \frac{{600}}{{300}} = 2\)

∴ कार्नोट ऊष्मा पंप का COP = 2

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