Question
Download Solution PDFएक कार्नोट ऊष्मा पंप 27°C और 327°C के बीच काम करता है। इसका COP क्या होगा?
This question was previously asked in
ESE Mechanical 2014 Official Paper - 1
Answer (Detailed Solution Below)
Option 4 : 2.0
Free Tests
View all Free tests >
ST 1: UPSC ESE (IES) Civil - Building Materials
6.1 K Users
20 Questions
40 Marks
24 Mins
Detailed Solution
Download Solution PDFअवधारणा:
\({\rm{COP\;of\;Carnot\;Heat\;pump}} = \frac{{{T_1}}}{{{T_1} - {T_2}}}\)
गणना:
दिया हुआ:
T1 = 327° C = 600 K, T2 = 27° C = 300 K
\(\therefore COP = \frac{{{T_1}}}{{{T_1} - {T_2}}}\)
\(\therefore COP = \frac{{600}}{{600 - 300}} = \frac{{600}}{{300}} = 2\)
∴ कार्नोट ऊष्मा पंप का COP = 2
Last updated on May 28, 2025
-> UPSC ESE admit card 2025 for the prelims exam has been released.
-> The UPSC IES Prelims 2025 will be held on 8th June 2025.
-> The selection process includes a Prelims and a Mains Examination, followed by a Personality Test/Interview.
-> Candidates should attempt the UPSC IES mock tests to increase their efficiency. The UPSC IES previous year papers can be downloaded here.