Question
Download Solution PDF8 m3/s निर्वहन 4 m चौड़े आयताकार चैनल से 2 m/s के वेग से बहता है। चैनल की द्रव-चालित माध्य त्रिज्या ___ है।
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसंकल्पना:
चैनल का नम क्षेत्र,
A = \(\frac{Q}{V}\)
इसलिए, नम परिधि,
P = (B + 2d)
चैनल की द्रवीय माध्य गहराई निम्नवत है
\(R = \frac{{\left( {Wetted\;Area,\;A} \right)}}{{\left( {Wetted\;Perimeter,\;P} \right)}}\)
गणना:
दिया गया है,
Q = 8 m3/s
B = 4 m
V = 2 m/s
चैनल का नम क्षेत्र,
A = \(\frac{Q}{V}\)
\(A = \frac{8}{2} = 4\;{m^2}\)
A = B × d
⇒ B × d = 4 m2
⇒ 4 × d = 4
⇒ d = 1 m
इसलिए, नम परिधि,
P = (B + 2d)
P = (4 + (2 × 1)) = 6 m
चैनल की द्रव-चालित माध्य गहराई निम्न है
\(R = \frac{{\left( {Wetted\;Area,\;A} \right)}}{{\left( {Wetted\;Perimeter,\;P} \right)}}\)
\(R = \frac{4}{6} = \frac{2}{3} \;m\)Last updated on Mar 26, 2025
-> UKPSC JE Notification for 2025 will be out soon!
-> The total number of vacancies along with application dates will be mentioned in the notification.
-> The exam will be conducted to recruit Junior Engineers through Uttarakhand Public Service Commission.
-> Candidates with an engineering diploma in the concerned field are eligible.
-> The selection process includes a written exam and document verification. Prepare for the exam with UKPSC JE Previous Year Papers.