Question
Download Solution PDFFor transverse electric waves between parallel plates, the lowest value of m, without making all the field components zero, is equal to
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
For parallel plate waveguide, the propagation constant is defined as:
\(\beta = \frac{{m\pi }}{a}\)
a = distance between the plates
Where the minimum value of m = 1
Cut-off frequency for the parallel plate waveguide is given by:
\({f_c} = \frac{m}{{2a}}\)
The wavelength will be:
\({\lambda _c} = \frac{{2a}}{m}\)
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