For n number of sides, the total sum of interior angles of a closed traverse is

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APSC JE Civil 14 Jul 2024 Official Paper
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  1. (n + 2) × 90°
  2. (2n - 4) × 90°
  3. (2n + 4) × 90°
  4. (4n - 2) × 90°

Answer (Detailed Solution Below)

Option 2 : (2n - 4) × 90°
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Explanation:

Sum of Interior Angles of a Closed Traverse

The sum of the interior angles of a closed traverse with n sides is derived using the formula for the sum of interior angles of a polygon. The general formula for the sum of interior angles of a polygon with n sides is:

Sum of interior angles = (n - 2) × 180°

This formula is derived from the fact that a polygon with n sides can be divided into (n - 2) triangles, and each triangle has an angle sum of 180°.

Now, since the question specifies the sum of angles in terms of multiples of 90°, we rewrite the formula:

Sum of interior angles = (n - 2) × 180° = (2n - 4) × 90°

Thus, the total sum of the interior angles of a closed traverse with n sides is:

(2n - 4) × 90°

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