Question
Download Solution PDFFor a second order system with denominator \(s^{2}+2 \delta w_{n} s+w_{n}^{2} ; w_{n}^{2}>0\) the roots are complex conjugates when
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
The standard second-order system has the characteristic equation:
\( s^2 + 2\zeta\omega_n s + \omega_n^2 = 0 \)
The roots of this equation determine the nature of the system (overdamped, underdamped, critically damped).
Condition for Complex Conjugate Roots:
Roots are complex conjugates if the discriminant is negative:
\( (2\zeta\omega_n)^2 - 4\omega_n^2 < 0 \Rightarrow \zeta^2 < 1 \)
So, complex roots exist when:
\( 0 \leq \zeta < 1 \)
Such systems are called underdamped systems.
Therefore, the correct answer is \( 0 \leq \zeta < 1 \)
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