Question
Download Solution PDFFind the smallest number which when divided by 4, 6, 7, 8 and 9 leaves the remainder 3 in each case.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
Find the smallest number which when divided by 4, 6, 7, 8 and 9 leaves the remainder 3 in each case.
Formula used:
Smallest number = LCM(4, 6, 7, 8, 9) + Remainder
Calculations:
LCM(4, 6, 7, 8, 9)
Prime factorization:
4 = 22
6 = 2 × 3
7 = 7
8 = 23
9 = 32
LCM = 23 × 32 × 7
LCM = 8 × 9 × 7
LCM = 504
Smallest number = 504 + 3
⇒ Smallest number = 507
∴ The correct answer is option 2.
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