Find the HCF of \(\rm \frac{1}{2}, \frac{2}{3}, \frac{3}{4}, \frac{4}{5}\) 

Given:

Find the HCF of \(\frac{1}{2}\),\(\frac{2}{3}\), \(\frac{3}{4}\), \(\frac{4}{5}\)

Formula used:

HCF of fractions = \(\frac{\text{HCF of numerators}}{\text{LCM of denominators}}\)

Calculation:

Numerators: 1, 2, 3, 4

Denominators: 2, 3, 4, 5

HCF of 1, 2, 3, 4 = 1

LCM of 2, 3, 4, 5

Prime factorization:

2 = 2

3 = 3

4 = 2 × 2

5 = 5

LCM = 2 × 2 × 3 × 5 = 60

⇒ HCF of fractions = \(\frac{1}{60}\)

∴ The correct answer is option 1.