Deflection of a simply supported beam at center of span, carrying a uniform load of w per unit run over entire span with uniform flexural rigidity is:

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Deflection of a simply supported beam at center of span, carrying a uniform load of w per unit run over entire span with uniform flexural rigidity is:

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OSSC JE Civil Mains Official Paper: (Held On: 16th July 2023)

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\( \left(\frac{5}{384}\right) w L^4 / E I\)
\( \left(\frac{1}{48}\right) w L^4 / E I\)
\( \left(\frac{5}{384}\right) w L^3 / E I \)
\(\left(\frac{3}{84}\right) \mathrm{wL}^3 / E I\)

Answer 1

The deflections of the beam with different support conditions are given below,

RRB JE CE R45 10Q Strength Of Materials(Hindi) 1

It can be seen that the deflection for simply supported beam of span ‘l’ carrying distributed load of ‘w’ per unit run over the whole span is given by,

Deflection = \(\frac{{5{\rm{w}}{{\rm{l}}^4}}}{{384{\rm{EI}}}}\)

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Deflection of a simply supported beam at center of span, carrying a uniform load of w per unit run over entire span with uniform flexural rigidity is:

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