An alternator is supplying a load of 300 kW at 0.6 p.f. lagging. If the power factor is raised to unity, how many more kilowatts can alternator supply for the same kVA loading?

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SSC JE EE Previous Year Paper 18 (Held On: 31 January 2016)
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  1. 100 kW
  2. 50 kW
  3. 200 kW
  4. 25 kW

Answer (Detailed Solution Below)

Option 3 : 200 kW
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Detailed Solution

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P = S cos ɸ

P = 300 kW, cos ɸ = 0.6

S = 300/0.6 = 500 kVA

Now, cos ɸ = 1, S = 500 kVA

P = 500 × 1 = 500 kW

More kilo watts can alternator supply for the same kVA loading = 500 – 300 = 200 kW
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