Question
Download Solution PDFA jet of water having a cross section area of 2 cm2 strikes a surface at speed 50 m/s. Estimate force applied to the surface by jet. Also calculate force applied by jet of air.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFExplanation-
Jet striking a stationary vertical plate-
Force acting on a plate due to the jet is given as, F = ρ A V2
Where a = Area of the jet, v = velocity of the jet, Density of fluid
Given data and Calculation- ×
Area of the jet = 2 cm2
Density of water = 1000 kg/m3
The density of air = 1.225 kg/m3
Velocity of jet = 50 m/s
Force applied by a jet of water,F = 1000 × 2 × 10-4 × 502
Fw = 500 N
Force applied by a jet of air,
F = 1.225 ×2 × 10-4 × 502
Fa = 0.6125 N
Last updated on May 19, 2025
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