Question
Download Solution PDFA helical compression spring of stiffness K is cut into two pieces, each having equal number of turns and kept side by side under compression. The equivalent spring stiffness of this new arrangement is equal to:
This question was previously asked in
ESE Mechanical 2015 Paper 2: Official Paper
Answer (Detailed Solution Below)
Option 1 : 4K
Free Tests
View all Free tests >
ST 1: UPSC ESE (IES) Civil - Building Materials
6.3 K Users
20 Questions
40 Marks
24 Mins
Detailed Solution
Download Solution PDFWhen spring is cut into two pieces, its stiffness will be doubled.
Last updated on May 28, 2025
-> UPSC ESE admit card 2025 for the prelims exam has been released.
-> The UPSC IES Prelims 2025 will be held on 8th June 2025.
-> The selection process includes a Prelims and a Mains Examination, followed by a Personality Test/Interview.
-> Candidates should attempt the UPSC IES mock tests to increase their efficiency. The UPSC IES previous year papers can be downloaded here.