Question
Download Solution PDFA car has an initial velocity of 12 m/s and is brought to rest over a distance of 45 m. The acceleration of the car is
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFCalculation:
Given:
Initial velocity, u = 12 m/s
Final velocity, v = 0 m/s (since the car comes to rest)
Distance, s = 45 m
Using the formula:
v2 = u2 + 2as
⇒ (0)2 = (12)2 + 2 × a × 45
⇒ 0 = 144 + 90a
⇒ 90a = -144
⇒ a = -1.6 m/s2
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