A 25 kW, 250 V, DC shunt generator has armature and field resistances of 0.06 Ω and 100 Ω, respectively. Find the armature current.

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MPPGCL JE Electrical 28 April 2023 Shift 2 Official Paper
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  1. 97.5 A
  2. 100 A
  3. 102.5 A
  4. 105 A

Answer (Detailed Solution Below)

Option 3 : 102.5 A
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MPPGCL JE Electrical Full Test 1
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Detailed Solution

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Concept

The circuit diagram of DC shunt generator is shown below:

qImage67d078e269433bf8f4c3f908

The current across the field resistance is given by:

\(I_{sh}={250\over 100}=2.5A\)

The load current is given by:

\(25\times 10^3=250\times I\)

I = 100 A

The armature current is:

\(I_a=I_{sh}+I_L\)

\(I_a=2.5+100\)

Ia = 102.5 A

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