Question
Download Solution PDFA 10-pole, three-phase, 50 Hz alternator has 180 slots. If the armature coils are short-pitched by two slots, what is the pitch factor?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept
The pitch factor is given by:
\(K_p=cos({α \over 2})\)
where, KP = Pitch factor
α = Short pitching angle
Calculation
Given, No. of slots = 180
Poles = 10
The armature coils are short-pitched by two slots. The angle contributed by one slot:
\(\theta={180\over slot/pole}\)
\(\theta={180\over 180/10}=10\)
The short pitched angle (α) = 2 × 10° = 20°
\(K_p=cos({20 \over 2})\)
KP = cos (10)°
Last updated on May 29, 2025
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