19-5-2025 IMG-649 Ankit -9

(1) 19-5-2025 IMG-649 Ankit -10 19-5-2025 IMG-649 Ankit -14 functional group isomers
(2) 19-5-2025 IMG-649 Ankit -11 19-5-2025 IMG-649 Ankit -15 Derivative
(3) 19-5-2025 IMG-649 Ankit -12 19-5-2025 IMG-649 Ankit -16 position isomers
(4) 19-5-2025 IMG-649 Ankit -13 19-5-2025 IMG-649 Ankit -17 chain isomers

 

  1. (1)
  2. (2)
  3. (3)
  4. (4)

Answer (Detailed Solution Below)

Option 3 : (3)

Detailed Solution

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To solve this problem, we need to follow the reaction steps and determine the structures of compounds B and C. Then we will determine the relationship between A and C.

Step 1: Identifying compound B

The reaction sequence starts with the given compound:

\(\text{A} = \text{Bromomethylbenzene} \ (C_6H_5CH_2Br)\)

Reacting with NaOH (aq) results in a nucleophilic substitution reaction where the bromine atom is replaced by a hydroxyl group:

\(\text{C}_6\text{H}_5\text{CH}_2\text{Br} \xrightarrow{\text{NaOH (aq)}} \text{C}_6\text{H}_5\text{CH}_2\text{OH}\)

So, compound B is benzyl alcohol:

19-5-2025 IMG-649 Ankit -18\(\text{B} = \text{Benzyl alcohol} \ (C_6H_5CH_2OH)\)

Step 2: Identifying compound C

Next, benzyl alcohol reacts with HBr in the presence of ether. This reaction is a typical substitution reaction where the hydroxyl group is replaced by a bromine atom:

\(\text{C}_6\text{H}_5\text{CH}_2\text{OH} \xrightarrow{\text{HBr, ether}} \text{C}_6\text{H}_5\text{CH}_2\text{Br}\)

So, compound C is the same as the original compound A:

\(\text{C} = \text{Bromomethylbenzene} \ (C_6H_5CH_2Br)\)

Step 3: Determining the relationship between A and C

Since compounds A and C have the same structure:

\(\text{A} = \text{C}_6\text{H}_5\text{CH}_2\text{Br} \\ \text{C} = \text{C}_6\text{H}_5\text{CH}_2\text{Br}\)

A and C are identical.

Since A and C are the same compound and B is benzyl alcohol,  and positional Isomer.

The most accurate representation of the relationship between A and C is Correct Answer: 3

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