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10 units are chosen by simple random sampling without replacement from a population of size 100. Consider the sample variance \(\frac{1}{10} \sum_{i=1}^{10}\left(y_i-\bar{y}\right)^2=s^2\). An unbiased estimate of population variance \(\sigma^2=\frac{1}{100} \sum_{i=1}^{100}\left(Y_i-\bar{Y}\right)^2\) is

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CSIR-UGC (NET) Mathematical Science: Held on (26 Nov 2020)
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  1. s2
  2. \(\frac{10}{11} s^2\)
  3. \(\frac{100}{99} s^2\)
  4. \(\frac{100}{111} s^2\)

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Option 1 : s2
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Last updated on Jul 8, 2025

-> The CSIR NET June 2025 Exam Schedule has been released on its official website.The exam will be held on 28th July 2025.

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