Errors and Approximations MCQ Quiz in বাংলা - Objective Question with Answer for Errors and Approximations - বিনামূল্যে ডাউনলোড করুন [PDF]

Last updated on Mar 22, 2025

পাওয়া Errors and Approximations उत्तरे आणि तपशीलवार उपायांसह एकाधिक निवड प्रश्न (MCQ क्विझ). এই বিনামূল্যে ডাউনলোড করুন Errors and Approximations MCQ কুইজ পিডিএফ এবং আপনার আসন্ন পরীক্ষার জন্য প্রস্তুত করুন যেমন ব্যাঙ্কিং, এসএসসি, রেলওয়ে, ইউপিএসসি, রাজ্য পিএসসি।

Latest Errors and Approximations MCQ Objective Questions

Top Errors and Approximations MCQ Objective Questions

Errors and Approximations Question 1:

The arm length of a cube is 10 cm. If the error in measuring the length of arm is 0.08 cm, the approximate value of the error in the volume of the cube will be:

  1. 12 cm3
  2. 15 cm3
  3. 24 cm3
  4. cm3

Answer (Detailed Solution Below)

Option 3 : 24 cm3

Errors and Approximations Question 1 Detailed Solution

Concept:

If an expression is A = 

The error per cent of A , =  +  +

Calculation:

Given arm length of the cube is 10 cm.

The error in the length of the arm is 0.08 cm.

⇒ Δ L = 0.08

∴  = 0.008.

We know that the volume of the cube is given by V = l3.

⇒ V = 103 = 1000 cm3

Error in the volume is given by:

⇒ 

⇒  = 3 × 0.008

⇒  = 0.024

⇒ Δ V = V × 0.024

⇒ Δ V = 1000 × 0.024

⇒ Δ V = 24

The approximate error in the volume of the cube is 24 cm3.

Errors and Approximations Question 2:

The value of is.

  1. 2.997
  2. 2.0997
  3. 2.00997
  4. 2.000997

Answer (Detailed Solution Below)

Option 1 : 2.997

Errors and Approximations Question 2 Detailed Solution

Concept: 

Let small charge in x be Δx and the corresponding change in y is Δy.

Therefore 

Calculation:

We have to find the value of 

Let x + Δx = 242 = 243 - 1

Therefore, x = 243 and Δx = - 1

Assume,           

Differentiating with respect to x, we get

At x = 243

 and y = 

As we know 

So, 

Therefore, approximate value of  = y + Δy = 3 - 0.0024 = 2.997

Errors and Approximations Question 3:

The value of  is

  1. 6.0833
  2. 6.00833
  3. 6.000833
  4. 6.0000833

Answer (Detailed Solution Below)

Option 3 : 6.000833

Errors and Approximations Question 3 Detailed Solution

Concept: 

Let small change in x be Δx and the corresponding change in y is Δy.

Therefore 

Calculation:

We have to find the value of 

Let x + Δx = 36.01 = 36 + 0.01

Therefore, x = 36 and Δx = -0.01

Assume,           

Differentiating with respect to x, we get

At x = 36

 and y = 

As we know 

So, 

Therefore, approximate value of  = y + Δy = 6 + 0.00083 = 6.00083

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