Question
Download Solution PDFWrite the chemical formula for the complex Iron (III) hexacyanoferrate (II) is
This question was previously asked in
AIIMS BSc NURSING 2023 Memory-Based Paper
Answer (Detailed Solution Below)
Option 1 : Fe4(Fe(CN)6]3
Free Tests
View all Free tests >
AIIMS BSc NURSING 2024 Memory-Based Paper
100 Qs.
100 Marks
120 Mins
Detailed Solution
Download Solution PDFCONCEPT:
Coordination Compounds and Complex Ions
- Coordination compounds consist of a central metal atom or ion bonded to surrounding ligands (molecules or ions).
- The formula of a coordination compound is written as [Metal(Ligand)n].
- The oxidation state of the metal ion is indicated in Roman numerals in parentheses.
EXPLANATION:
- In the given complex, Iron (III) hexacyanoferrate (II):
- Iron (III) indicates that the central iron ion has an oxidation state of +3.
- Hexacyanoferrate (II) indicates that the hexacyanoferrate ion has an iron ion with an oxidation state of +2 and is coordinated with six cyanide (CN-) ligands.
- The hexacyanoferrate (II) ion is [Fe(CN)6]4-, because each CN has a -1 charge and there are 6 of them, making the total charge of the ion -4.
- To balance the charges, three Fe3+ ions are needed to neutralize the charge of four [Fe(CN)6]4- ions.
Therefore, the chemical formula for Iron (III) hexacyanoferrate (II) is Fe4[Fe(CN)6]3.
Last updated on Jun 17, 2025
-> The AIIMS BSc Nursing (Hons) Result 2025 has been announced.
->The AIIMS BSc Nursing (Hons) Exam was held on 1st June 2025
-> The exam for BSc Nursing (Post Basic) will be held on 21st June 2025.
-> AIIMS BSc Nursing Notification 2025 was released for admission to the 2025 academic session.