White light reflected from a soap film (Refractive Index = 1.5) has a maxima at 600 nm and a minima at 750 nm with no minimum in between. Then the thickness of the film is ______ × 10-7 m.

  1. 1
  2. 2
  3. 5
  4. 3

Answer (Detailed Solution Below)

Option 3 : 5
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CONCEPT:

  • Interference: A phenomenon in which two waves superpose on each other to form a resultant wave of greater, lower, or the same amplitude is called interference.
  • Thin-film interference: When light waves reflecting off from the top and bottom surfaces of a thin film interfere with another

Due to interference in Thin Films, there occurs maxima and minima.

For maxima:

for minima:

where μ is the refractive index of thin film, t is the thickness of soap film, r is the angle of reflection, n is the nth fringe, and λ is the wavelength.

CALCULATION:

Given that

 λ1 = 600nm; 

λ2 = 750 nm;

μ = 1.5

For maxima

....... (i)

for minima

............(ii)

divide eq (i) and eq (ii)

n = 2

put in eq (ii)

t = 500 nm = 5 × 10-7

so the correct answer is option 3.

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