A convex lens has power P. It is cut into two halves along its principal axis. Further one piece (out of the two halves) is cut into two halves perpendicular to the principal axis (as shown in figure). Choose the incorrect option for the reported pieces. 

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  1. Power of \(\mathrm{L}_{1}=\frac{\mathrm{P}}{2}\)
  2. Power of \(\mathrm{~L}_{2}=\frac{\mathrm{P}}{2} \)
  3. Power of \(\mathrm{~L}_{3}=\frac{\mathrm{P}}{2}\)
  4. Power of L1 = P

Answer (Detailed Solution Below)

Option 1 : Power of \(\mathrm{L}_{1}=\frac{\mathrm{P}}{2}\)
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Detailed Solution

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Concept :

When a convex lens is cut along the principal axis, the power of each half remains the same as the original lens. When further cut perpendicular to the principal axis, the power of each piece is halved.

Calculation:

Let's denote the pieces as L1, L2, and L3 as shown in the figure.

⇒ The original lens has power P.

⇒ When cut along the principal axis, the power of each half remains the same:

⇒ Power of L1 = Power of L2 = P

⇒ When L2 is further cut perpendicular to the principal axis:

⇒ Power of each piece (L2 and L3) becomes P/2.

⇒ Power of L2 = P/2

⇒ Power of L3 = P/2

The incorrect option is:

1) Power of L1 = P/2

Therefore, the correct answer is option 1.

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